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Popular >

y^'=-1/2 y

Solution

y^{^{'}} = - \frac{1}{2} y

Solution

y = e^{\frac{- t - c _{1}}{2}}

Solution steps

y^{'} (t) = - \frac{1}{2} y

Solve separable ODE:

y = e^{\frac{- t - c _{1}}{2}}

y = e^{\frac{- t - c _{1}}{2}}

Graph

Popular Examples

integral of ((12)/x+x/(12))

\int (\frac{12}{x} + \frac{x}{12}) d x

xy^'+3y=(2e^{4x})/(x^2)

x y^{^{'}} + 3 y = \frac{2 e ^{4 x}}{x ^{2}}

derivative of ax^2e^{-x}

\frac{d}{d x} (a x^{2} e^{- x})

derivative of ln(3/(x^2+9))

\frac{d}{d x} (ln (\frac{3}{x ^{2} + 9}))

tangent of f(x)=x^x,\at x=2 tangent of

f (x) = x^{x}, at x = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=-1/2 y ?
The solution for y^'=-1/2 y is y=e^{(-t-c_{1})/2}