What is the integral of \sqrt[4]{x} ?

The integral of \sqrt[4]{x} is 4/5 x^{5/4}+C

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integral of \sqrt[4]{x}

\int 4 x d x

\frac{4}{5} x^{\frac{5}{4}} + C

Solution steps

\int 4 x d x

Apply the Power Rule

: \frac{4}{5} x^{\frac{5}{4}}

= \frac{4}{5} x^{\frac{5}{4}}

Add a constant to the solution

= \frac{4}{5} x^{\frac{5}{4}} + C

x \to 4 lim (\frac{x ^{4} - 256}{x ^{3} - 64})

(1 + x^{2})^{- \frac{3}{2}}

\frac{d}{d x} (\frac{x ^{2} + 2 x - 2}{( x + 1 ) ^{2}})

f (x) = \frac{7}{x}, x = 1, x = 41

x \to 3 + lim (\frac{6 x}{x ^{2} - 9})

What is the integral of \sqrt[4]{x} ?
The integral of \sqrt[4]{x} is 4/5 x^{5/4}+C