What is (\partial)/(\partial x)(x^2-5x^2y-6xy^2) ?

The answer to (\partial)/(\partial x)(x^2-5x^2y-6xy^2) is 2x-10yx-6y^2

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(\partial)/(\partial x)(x^2-5x^2y-6xy^2)

\frac{\partial}{\partial x} (x^{2} - 5 x^{2} y - 6 x y^{2})

2 x - 10 y x - 6 y^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} - 5 x^{2} y - 6 x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (5 x^{2} y) - \frac{\partial}{\partial x} (6 x y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (5 x^{2} y) = 10 y x

\frac{\partial}{\partial x} (6 x y^{2}) = 6 y^{2}

= 2 x - 10 y x - 6 y^{2}

\int \frac{x ^{2} - x}{1 + 3 x ^{2} - 2 x ^{3}} d x

y = (x^{2} + 1)

\int \frac{36 + ( ln ( 8 x ) ) ^{2}}{x} d x

x \to 0 lim (\frac{x ^{2} - 9}{x + 3})

y^{^{'}} = \frac{( x + y + 1 )}{( 2 x + 2 y + 3 )}

What is (\partial)/(\partial x)(x^2-5x^2y-6xy^2) ?
The answer to (\partial)/(\partial x)(x^2-5x^2y-6xy^2) is 2x-10yx-6y^2