What is the integral from 0 to 9 of pi(9-y) ?

The integral from 0 to 9 of pi(9-y) is pi 81/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 9 of pi(9-y)

\int_{0}^{9} π (9 - y) d y

π \frac{81}{2}

Decimal

127.23450 \dots

Solution steps

\int_{0}^{9} π (9 - y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{9} 9 - y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{9} 9 d y - \int_{0}^{9} y d y)

\int_{0}^{9} 9 d y = 81

\int_{0}^{9} y d y = \frac{81}{2}

= π (81 - \frac{81}{2})

Join

81 - \frac{81}{2} : \frac{81}{2}

= π \frac{81}{2}

f (x) = 49 - x^{2}

- \frac{x}{4 y}

\frac{d}{d x} ((x + 6) (x - 2)^{2})

\frac{d}{d x} (\frac{1}{5 - x})

\frac{\partial}{\partial x} (x^{2} y - y^{2} x)

What is the integral from 0 to 9 of pi(9-y) ?
The integral from 0 to 9 of pi(9-y) is pi 81/2