What is the tangent of f(x)= 3/(sqrt(x)),(1,3) ?

The tangent of f(x)= 3/(sqrt(x)),(1,3) is y=-3/2 x+9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 3/(sqrt(x)),(1,3)

tangent of

f (x) = \frac{3}{x}, (1, 3)

y = - \frac{3}{2} x + \frac{9}{2}

Solution steps

Find the slope of

f (x) = \frac{3}{x} : \frac{df ( x )}{d x} = - \frac{3}{2 x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(1, 3) : y = - \frac{3}{2} x + \frac{9}{2}

y = - \frac{3}{2} x + \frac{9}{2}

y \to 0 lim (\frac{8}{y ^{2} + y} - \frac{8}{y})

y^{^{''}} + 3 y^{^{'}} - 10 y = x (e^{x} + 1)

\frac{d}{d x} (3^{- 6 x + 6})

f^{^{'}} (x) = 3 x^{2} (8 - x^{- 3})

\int_{0}^{1} 5^{2 x} d x

What is the tangent of f(x)= 3/(sqrt(x)),(1,3) ?
The tangent of f(x)= 3/(sqrt(x)),(1,3) is y=-3/2 x+9/2