en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+y=-e^x

Solution

y^{^{'}} + y = - e^{x}

Solution

y = - \frac{e ^{x}}{2} + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y = - e^{x}

Solve linear ODE:

y = - \frac{e ^{x}}{2} + \frac{c _{1}}{e ^{x}}

y = - \frac{e ^{x}}{2} + \frac{c _{1}}{e ^{x}}

Graph

Popular Examples

integral of (x+1)sqrt(7-x)

\int (x + 1) 7 - x d x

integral from 0 to 1 of t^3e^{-2t}

\int_{0}^{1} t^{3} e^{- 2 t} d t

limit as x approaches 0 of (e^x-1)/(x^2)

x \to 0 lim (\frac{e ^{x} - 1}{x ^{2}})

area y=x^2-12,y=4x area

y = x^{2} - 12, y = 4 x

(dy)/(dx)(2+x)=3y

\frac{d y}{d x} (2 + x) = 3 y

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=-e^x ?
The solution for y^'+y=-e^x is y=-(e^x)/2+(c_{1})/(e^x)