What is the derivative of tan(x)-1sec(x) ?

The derivative of tan(x)-1sec(x) is 1/(1+sin(x))

What is the first derivative of tan(x)-1sec(x) ?

The first derivative of tan(x)-1sec(x) is 1/(1+sin(x))

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derivative of

tan (x) - 1 sec (x)

\frac{1}{1 + sin ( x )}

Solution steps

\frac{d}{d x} (tan (x) - 1 \cdot sec (x))

Simplify

tan (x) - 1 \cdot sec (x) : tan (x) - sec (x)

= \frac{d}{d x} (tan (x) - sec (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (tan (x)) - \frac{d}{d x} (sec (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= sec^{2} (x) - sec (x) tan (x)

Simplify

sec^{2} (x) - sec (x) tan (x) : \frac{1}{1 + sin ( x )}

= \frac{1}{1 + sin ( x )}

\int y^{2} + 1 d y

y = sin (sin (x)), at x = π

y = x, (9, 3)

\frac{sin ( x ) + cos ( x )}{cos ( x )}

What is the derivative of tan(x)-1sec(x) ?
The derivative of tan(x)-1sec(x) is 1/(1+sin(x))
What is the first derivative of tan(x)-1sec(x) ?
The first derivative of tan(x)-1sec(x) is 1/(1+sin(x))