What is the derivative of sin^3(t) ?

The derivative of sin^3(t) is 3sin^2(t)cos(t)

What is the first derivative of sin^3(t) ?

The first derivative of sin^3(t) is 3sin^2(t)cos(t)

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derivative of

sin^{3} (t)

3 sin^{2} (t) cos (t)

Solution steps

\frac{d}{d t} (sin^{3} (t))

Apply the chain rule:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 3 (sin (t))^{2} cos (t)

Simplify

= 3 sin^{2} (t) cos (t)

\int \frac{1}{8 y} d y

\int sec^{2} (x) tan^{5} (x) d x

\frac{d y}{d x} + 2 x y = - x

t y^{^{'}} + 8 y = t^{2} - t + 1

\frac{d}{d x} (\frac{1}{( 25 - x ^{2} )})

What is the derivative of sin^3(t) ?
The derivative of sin^3(t) is 3sin^2(t)cos(t)
What is the first derivative of sin^3(t) ?
The first derivative of sin^3(t) is 3sin^2(t)cos(t)