What is the solution for (dy)/(dx)=(2xy-y^2)/(x^2) ?

The solution for (dy)/(dx)=(2xy-y^2)/(x^2) is y=(x^2)/(x+c_{1)}

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(dy)/(dx)=(2xy-y^2)/(x^2)

\frac{d y}{d x} = \frac{2 x y - y ^{2}}{x ^{2}}

y = \frac{x ^{2}}{x + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{2 x y - y ^{2}}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x ^{2}}{x + c _{1}}

y = \frac{x ^{2}}{x + c _{1}}

\frac{d y}{d x} = \frac{4 x ^{3}}{cos ( y )}

\frac{d}{d x} ((2 x - 1) (3 x + 5))

x \to 2 - lim (x^{2} + 2)

\int x^{3} - 6 x + 7 d x

\frac{d}{d x} (x (x - 1)^{4})

What is the solution for (dy)/(dx)=(2xy-y^2)/(x^2) ?
The solution for (dy)/(dx)=(2xy-y^2)/(x^2) is y=(x^2)/(x+c_{1)}