What is the derivative of 6x^2-96x ?

The derivative of 6x^2-96x is 12x-96

What is the first derivative of 6x^2-96x ?

The first derivative of 6x^2-96x is 12x-96

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\frac{d}{d x} (6 x^{2} - 96 x)

12 x - 96

Solution steps

\frac{d}{d x} (6 x^{2} - 96 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{2}) - \frac{d}{d x} (96 x)

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (96 x) = 96

= 12 x - 96

\int (2 x + 1)^{4} d x

\int_{0}^{8} 2 t^{2} - 24 t + 70 d t

y^{^{'}} = \frac{1 + y ^{2}}{1 + x ^{2}}

\int \frac{1}{s ^{2}} d s

x \to - 1 lim (\frac{x - 1}{x ^{2} - 1})

What is the derivative of 6x^2-96x ?
The derivative of 6x^2-96x is 12x-96
What is the first derivative of 6x^2-96x ?
The first derivative of 6x^2-96x is 12x-96