What is the integral of 4(1+tan^2(x)) ?

The integral of 4(1+tan^2(x)) is 4tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 4(1+tan^2(x))

\int 4 (1 + tan^{2} (x)) d x

4 tan (x) + C

Solution steps

\int 4 (1 + tan^{2} (x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int 1 + tan^{2} (x) d x

Rewrite using trig identities

= 4 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 4 tan (x)

Add a constant to the solution

= 4 tan (x) + C

y^{^{''}} + 2 y^{^{'}} = 2 x + 5 - e^{-} 2 x

\frac{d}{d x} (\frac{2 x ^{3} - 7}{x ^{2}})

\frac{d y}{d x} = 100 - y

x \to \infty lim ((1 + \frac{1}{2 x + 1})^{x^{2 - 3}})

\int_{0}^{1} (x^{2} - 3 x + 6) d x

What is the integral of 4(1+tan^2(x)) ?
The integral of 4(1+tan^2(x)) is 4tan(x)+C