What is the solution for (dy)/(dx)=ysin(x),y(0)=1 ?

The solution for (dy)/(dx)=ysin(x),y(0)=1 is y=e^{-cos(x)+1}

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(dy)/(dx)=ysin(x),y(0)=1

\frac{d y}{d x} = y sin (x), y (0) = 1

y = e^{- c o s (x) + 1}

Solution steps

\frac{d y}{d x} = y sin (x)

Solve separable ODE:

y = e^{- c o s (x) + 1}

y = e^{- c o s (x) + 1}

\int e^{x y} d x

f (x) = \frac{1 + 16 x ^{2}}{( 4 x ) ^{3}}

y^{^{''}} - y^{^{'}} = 0, y (0) = 10

\int \frac{4}{3 - x} d x

\frac{\partial}{\partial x} (x^{2} - x y - y^{2})

What is the solution for (dy)/(dx)=ysin(x),y(0)=1 ?
The solution for (dy)/(dx)=ysin(x),y(0)=1 is y=e^{-cos(x)+1}