What is the integral from 2 to 3 of (24)/(sqrt(3-x)) ?

The integral from 2 to 3 of (24)/(sqrt(3-x)) is 48

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integral from 2 to 3 of (24)/(sqrt(3-x))

\int_{2}^{3} \frac{24}{3 - x} d x

48

Solution steps

\int_{2}^{3} \frac{24}{3 - x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 24 \cdot \int_{2}^{3} \frac{1}{3 - x} d x

Apply u-substitution

: \int_{1}^{0} - \frac{1}{u} d u

= 24 \cdot \int_{1}^{0} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= 24 (- \int_{0}^{1} - \frac{1}{u} d u)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 24 (- (- \int_{0}^{1} \frac{1}{u} d u))

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{0}^{1}

= 24 (- (- [2 u^{\frac{1}{2}}]_{0}^{1}))

Simplify

24 (- (- [2 u^{\frac{1}{2}}]_{0}^{1})) : 24 [2 u]_{0}^{1}

= 24 [2 u]_{0}^{1}

Compute the boundaries:

2

= 24 \cdot 2

Simplify

= 48

f (x) = \frac{5}{ln ( x )}

\frac{d}{d x} ((x - a)^{3})

\int \frac{sin ( \frac{1}{x ^{2}} )}{x ^{3}} d x

\int \frac{( x + 3 )}{x ^{2} + 4} d x

\int \frac{1}{x ( 1 + x )} d x

What is the integral from 2 to 3 of (24)/(sqrt(3-x)) ?
The integral from 2 to 3 of (24)/(sqrt(3-x)) is 48