What is (\partial)/(\partial y)(25-x^2-y^2) ?

The answer to (\partial)/(\partial y)(25-x^2-y^2) is -2y

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(\partial)/(\partial y)(25-x^2-y^2)

\frac{\partial}{\partial y} (25 - x^{2} - y^{2})

- 2 y

Solution steps

\frac{\partial}{\partial y} (25 - x^{2} - y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (25) - \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (25) = 0

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 - 0 - 2 y

Simplify

= - 2 y

\frac{d}{d x} (arctan (8 x))

y = (9 x)^{3 x}

\int \frac{1}{x ( x - 5 ) ^{2}} d x

\frac{d}{d x} (ln (\frac{1}{x} + \frac{1}{x ^{2}}))

\int \frac{3 x - 5}{x ^{2} ( x + 5 )} d x

What is (\partial)/(\partial y)(25-x^2-y^2) ?
The answer to (\partial)/(\partial y)(25-x^2-y^2) is -2y