What is (\partial)/(\partial x)(2x+3y-6) ?

The answer to (\partial)/(\partial x)(2x+3y-6) is 2

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(\partial)/(\partial x)(2x+3y-6)

\frac{\partial}{\partial x} (2 x + 3 y - 6)

2

Solution steps

\frac{\partial}{\partial x} (2 x + 3 y - 6)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (3 y) - \frac{\partial}{\partial x} (6)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (3 y) = 0

\frac{\partial}{\partial x} (6) = 0

= 2 + 0 - 0

Simplify

= 2

(9 - x^{3})^{- 2}

\frac{d}{d x} (\frac{1}{4} x^{4} - 2 x^{3} + \frac{9}{2} x^{2} + 1)

\int_{0}^{3} \frac{1}{x ^{2} + 3} d x

1 - x - x^{2}

\int tan^{3} (x) sec^{9} (x) d x

What is (\partial)/(\partial x)(2x+3y-6) ?
The answer to (\partial)/(\partial x)(2x+3y-6) is 2