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Popular >

integral from 0 to 1 of x+y

Solution

\int_{0}^{1} x + y d y

Solution

x + \frac{1}{2}

Solution steps

\int_{0}^{1} x + y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x d y + \int_{0}^{1} y d y

\int_{0}^{1} x d y = x

\int_{0}^{1} y d y = \frac{1}{2}

= x + \frac{1}{2}

Popular Examples

integral from 3 to 6 of (x-4)^2

\int_{3}^{6} (x - 4)^{2} d x

integral of sqrt(1-(x^2)/4)

\int 1 - \frac{x ^{2}}{4} d x

integral of (2^t+e^pi)

\int (2^{t} + e^{π}) d t

y^'=e^{4x}(cos(x)+sin(x))

y^{^{'}} = e^{4 x} (cos (x) + sin (x))

(\partial)/(\partial z)((x^2-y^2)/(z^2))

\frac{\partial}{\partial z} (\frac{x ^{2} - y ^{2}}{z ^{2}})

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of x+y ?
The integral from 0 to 1 of x+y is x+1/2