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Popular >

x^2y^'=xy+y^2

Solution

x^{2} y^{^{'}} = x y + y^{2}

Solution

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

x^{2} y^{'} (x) = x y + y^{2}

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

Graph

Popular Examples

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\int x (x + 4)^{7} d x

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\int \frac{10 sin ( 2 x )}{1 + cos ^{4} ( x )} d x

(dy)/(dx)y=ln(2)(x+3)

\frac{d y}{d x} y = ln (2) (x + 3)

integral of (x+8)/(2x^3-18x)

\int \frac{x + 8}{2 x ^{3} - 18 x} d x

integral of ln(4)

\int ln (4)

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'=xy+y^2 ?
The solution for x^2y^'=xy+y^2 is y= x/(-ln(x)+c_{1)}