What is the derivative of 2e^x-8^x ?

The derivative of 2e^x-8^x is 2e^x-3ln(2)*8^x

What is the first derivative of 2e^x-8^x ?

The first derivative of 2e^x-8^x is 2e^x-3ln(2)*8^x

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\frac{d}{d x} (2 e^{x} - 8^{x})

2 e^{x} - 3 ln (2) \cdot 8^{x}

Solution steps

\frac{d}{d x} (2 e^{x} - 8^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{x}) - \frac{d}{d x} (8^{x})

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

\frac{d}{d x} (8^{x}) = 3 ln (2) \cdot 8^{x}

= 2 e^{x} - 3 ln (2) \cdot 8^{x}

\int \frac{1}{x ^{2} - 144} d x

\frac{\partial}{\partial x} (2 y^{3} - 6 y + x^{2})

\int_{0}^{\frac{π}{2}} x sin (x) d x

x \to 1 lim (+ f (x))

\int_{0}^{1} 4 - y - 2 y - 1 d y

What is the derivative of 2e^x-8^x ?
The derivative of 2e^x-8^x is 2e^x-3ln(2)*8^x
What is the first derivative of 2e^x-8^x ?
The first derivative of 2e^x-8^x is 2e^x-3ln(2)*8^x