What is the derivative of 3+sqrt(x) ?

The derivative of 3+sqrt(x) is 1/(2sqrt(x))

What is the first derivative of 3+sqrt(x) ?

The first derivative of 3+sqrt(x) is 1/(2sqrt(x))

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\frac{d}{d x} (3 + x)

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (3 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (x)

\frac{d}{d x} (3) = 0

\frac{d}{d x} (x) = \frac{1}{2 x}

= 0 + \frac{1}{2 x}

Simplify

= \frac{1}{2 x}

\frac{d y}{d x} = 0.6 y

\int e^{x^{3}} \cdot x^{2} d x

\frac{d}{d x} (arctan (sinh (x)))

\frac{d}{d x} ((a x^{2} + b x + c) e^{- \frac{x}{4}})

f (x) = \frac{14}{( 1 + e ^{- x} ) , at ( 0 , 7 )}

What is the derivative of 3+sqrt(x) ?
The derivative of 3+sqrt(x) is 1/(2sqrt(x))
What is the first derivative of 3+sqrt(x) ?
The first derivative of 3+sqrt(x) is 1/(2sqrt(x))