What is (\partial)/(\partial y)(2x^3y+1) ?

The answer to (\partial)/(\partial y)(2x^3y+1) is 2x^3

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(\partial)/(\partial y)(2x^3y+1)

\frac{\partial}{\partial y} (2 x^{3} y + 1)

2 x^{3}

Solution steps

\frac{\partial}{\partial y} (2 x^{3} y + 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{3} y) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (2 x^{3} y) = 2 x^{3}

\frac{\partial}{\partial y} (1) = 0

= 2 x^{3} + 0

Simplify

= 2 x^{3}

\frac{d}{d x} (4 + 4 x^{\frac{3}{2}})

n = 1 \sum \infty (\frac{3}{4})^{n}

\frac{d}{d t} (sin (2 t))

\int e^{4 x} cos (5 x) d x

\frac{1}{14 x ^{2}}, \frac{x}{4}, 0, 3 \frac{1}{14}

What is (\partial)/(\partial y)(2x^3y+1) ?
The answer to (\partial)/(\partial y)(2x^3y+1) is 2x^3