What is the sum from n=0 to infinity of (-3/4)^n ?

The sum from n=0 to infinity of (-3/4)^n is 4/7

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sum from n=0 to infinity of (-3/4)^n

n = 0 \sum \infty (- \frac{3}{4})^{n}

\frac{4}{7}

Solution steps

n = 0 \sum \infty (- \frac{3}{4})^{n}

Apply Series Geometric Test:

\frac{4}{7}

= \frac{4}{7}

y = 3 x + 1, (0, 3)

\frac{x d y}{d x} = 3 x e^{x} - y + 6 x^{2}

\frac{\partial}{\partial x} (5 x^{3} + 4 x y^{3})

\int \frac{x ^{2} + 1}{x} d x

n = 1 \sum \infty \frac{x ^{n - 1}}{x}

What is the sum from n=0 to infinity of (-3/4)^n ?
The sum from n=0 to infinity of (-3/4)^n is 4/7