What is the solution for t((dy)/(dt))+5y=4t,y(1)=2 ?

The solution for t((dy)/(dt))+5y=4t,y(1)=2 is y=(2t)/3+4/(3t^5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t((dy)/(dt))+5y=4t,y(1)=2

t (\frac{d y}{d t}) + 5 y = 4 t, y (1) = 2

y = \frac{2 t}{3} + \frac{4}{3 t ^{5}}

Solution steps

t (\frac{d y}{d t}) + 5 y = 4 t

Solve linear ODE:

y = \frac{2 t}{3} + \frac{4}{3 t ^{5}}

y = \frac{2 t}{3} + \frac{4}{3 t ^{5}}

x^{- \frac{3}{2}}

x \to + 5 lim (x^{2} - 2 x + 1)

\int \frac{2 + e ^{x}}{2 - e ^{x}} d x

\frac{\partial}{\partial x} (ln (e^{x y} cos (x)))

\frac{d}{d x} ((1 - x^{- 1})^{- 1})

What is the solution for t((dy)/(dt))+5y=4t,y(1)=2 ?
The solution for t((dy)/(dt))+5y=4t,y(1)=2 is y=(2t)/3+4/(3t^5)