What is (\partial)/(\partial y)(y+1) ?

The answer to (\partial)/(\partial y)(y+1) is 1

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(\partial)/(\partial y)(y+1)

\frac{\partial}{\partial y} (y + 1)

1

Solution steps

\frac{\partial}{\partial y} (y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (1) = 0

= 1 + 0

Simplify

= 1

\frac{6}{( s + 1 ) ( 2 s ^{2} + 5 s + 3 )}

\int_{0}^{1} \frac{x ^{2}}{( x + 3 ) ^{2}} d x

\int e^{10 x} \cdot 5 x d x

x = 4 y, x = y^{2} - 5

\int_{- 4}^{4} (2 x^{7} + 1) d x

What is (\partial)/(\partial y)(y+1) ?
The answer to (\partial)/(\partial y)(y+1) is 1