What is area f(x)=x^3-6x,g(x)=-2x ?

The answer to area f(x)=x^3-6x,g(x)=-2x is 8

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area f(x)=x^3-6x,g(x)=-2x

area

f (x) = x^{3} - 6 x, g (x) = - 2 x

8

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{3} - 4 x d x

Solve

\int_{- 2}^{2} x^{3} - 4 x d x : 8

The area is:

= 8

36 t^{2}

\int x^{2} 3 x + 6 d x

\int (\frac{y ^{4} + 2 y ^{2} - 1}{y}) d y

\frac{\partial}{\partial z} (x yz + x y^{4} + y z^{4} + z x^{4})

\frac{\partial}{\partial z} (x sin (y))

What is area f(x)=x^3-6x,g(x)=-2x ?
The answer to area f(x)=x^3-6x,g(x)=-2x is 8