What is the d/(dt)(sin(6t)) ?

The d/(dt)(sin(6t)) is cos(6t)*6

What is the first d/(dt)(sin(6t)) ?

The first d/(dt)(sin(6t)) is cos(6t)*6

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\frac{d}{d t} (sin (6 t))

cos (6 t) \cdot 6

Solution steps

\frac{d}{d t} (sin (6 t))

Apply the chain rule:

cos (6 t) \frac{d}{d t} (6 t)

= cos (6 t) \frac{d}{d t} (6 t)

\frac{d}{d t} (6 t) = 6

= cos (6 t) \cdot 6

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