What is the derivative of f(x)=ln(4x+1) ?

The derivative of f(x)=ln(4x+1) is 4/(4x+1)

What is the first derivative of f(x)=ln(4x+1) ?

The first derivative of f(x)=ln(4x+1) is 4/(4x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = ln (4 x + 1)

\frac{4}{4 x + 1}

Solution steps

\frac{d}{d x} (ln (4 x + 1))

Apply the chain rule:

\frac{1}{4 x + 1} \frac{d}{d x} (4 x + 1)

= \frac{1}{4 x + 1} \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= \frac{1}{4 x + 1} \cdot 4

Simplify

\frac{1}{4 x + 1} \cdot 4 : \frac{4}{4 x + 1}

= \frac{4}{4 x + 1}

\frac{d}{d x} (\frac{1}{ln ^{2} ( x )})

\int \frac{1}{x 9 x ^{2} + 16} d x

\int t^{2} t^{3} + 1 d t

\int \frac{r ^{3}}{4 + r ^{2}} d r

x \to 2 - lim (\frac{1 - x}{x - 2})

What is the derivative of f(x)=ln(4x+1) ?
The derivative of f(x)=ln(4x+1) is 4/(4x+1)
What is the first derivative of f(x)=ln(4x+1) ?
The first derivative of f(x)=ln(4x+1) is 4/(4x+1)