What is the derivative of-x-1/x ?

The derivative of-x-1/x is -1+1/(x^2)

What is the first derivative of-x-1/x ?

The first derivative of-x-1/x is -1+1/(x^2)

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derivative of

- x - \frac{1}{x}

- 1 + \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (- x - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} - \frac{d}{d x} (\frac{1}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= - 1 - (- \frac{1}{x ^{2}})

Simplify

= - 1 + \frac{1}{x ^{2}}

x \to 0 lim (x^{- 1})

\int_{- 2}^{3} \frac{14}{x ^{4}} d x

\frac{d}{d x} (x e^{x} sin (y))

y^{^{''}} + 3 y^{^{'}} - 7 y = x^{4} e^{x}

y = x^{2} - 2 x + 2, y = 4

What is the derivative of-x-1/x ?
The derivative of-x-1/x is -1+1/(x^2)
What is the first derivative of-x-1/x ?
The first derivative of-x-1/x is -1+1/(x^2)