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Popular >

y^'=3y+7,y(0)=4

Solution

y^{^{'}} = 3 y + 7, y (0) = 4

Solution

y = \frac{19 e ^{3 t}}{3} - \frac{7}{3}

Solution steps

y^{'} (t) = 3 y + 7

Solve separable ODE:

y = \frac{19 e ^{3 t}}{3} - \frac{7}{3}

y = \frac{19 e ^{3 t}}{3} - \frac{7}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=3y+7,y(0)=4 ?
The solution for y^'=3y+7,y(0)=4 is y=(19e^{3t})/3-7/3