What is the derivative of 1-ln(3x) ?

The derivative of 1-ln(3x) is -1/x

What is the first derivative of 1-ln(3x) ?

The first derivative of 1-ln(3x) is -1/x

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derivative of

1 - ln (3 x)

- \frac{1}{x}

Solution steps

\frac{d}{d x} (1 - ln (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (ln (3 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (ln (3 x)) = \frac{1}{x}

= 0 - \frac{1}{x}

Simplify

= - \frac{1}{x}

f (x) = 3 x^{2}, at x = 1

\frac{d}{d x} (x (4 x + 1)^{\frac{1}{3}})

\int \frac{t}{t - 2} d t

\int \frac{1}{x - c} d x

\int \frac{x ^{4} - 2 x ^{2} + 1}{x ^{3}} d x

What is the derivative of 1-ln(3x) ?
The derivative of 1-ln(3x) is -1/x
What is the first derivative of 1-ln(3x) ?
The first derivative of 1-ln(3x) is -1/x