What is the derivative of (x^2+6^9) ?

The derivative of (x^2+6^9) is 18x(x^2+6)^8

What is the first derivative of (x^2+6^9) ?

The first derivative of (x^2+6^9) is 18x(x^2+6)^8

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\frac{d}{d x} ((x^{2} + 6)^{9})

18 x (x^{2} + 6)^{8}

Solution steps

\frac{d}{d x} ((x^{2} + 6)^{9})

Apply the chain rule:

9 (x^{2} + 6)^{8} \frac{d}{d x} (x^{2} + 6)

= 9 (x^{2} + 6)^{8} \frac{d}{d x} (x^{2} + 6)

\frac{d}{d x} (x^{2} + 6) = 2 x

= 9 (x^{2} + 6)^{8} \cdot 2 x

Simplify

= 18 x (x^{2} + 6)^{8}

\frac{d}{d x} (cosh (4 x))

\int \frac{2 x ^{2} + 7 x - 8}{x - 7} d x

\frac{\partial}{\partial y} (e^{2 x + 3 y})

x \to 1 + lim (x + 2)

\int \frac{x}{( x - 1 ) ( x ^{2} + 2 x + 2 )} d x

What is the derivative of (x^2+6^9) ?
The derivative of (x^2+6^9) is 18x(x^2+6)^8
What is the first derivative of (x^2+6^9) ?
The first derivative of (x^2+6^9) is 18x(x^2+6)^8