What is the derivative of (x^2+3x^2) ?

The derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)

What is the first derivative of (x^2+3x^2) ?

The first derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)

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\frac{d}{d x} ((x^{2} + 3 x)^{2})

2 (x^{2} + 3 x) (2 x + 3)

Solution steps

\frac{d}{d x} ((x^{2} + 3 x)^{2})

Apply the chain rule:

2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

= 2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= 2 (x^{2} + 3 x) (2 x + 3)

\frac{16 x ^{3}}{3} - 4 x^{2} + 6 x - 13

\int_{0}^{3} (3 x + 2) d x

\int tan (d) x d x

\frac{\partial}{\partial x} ((x + 1)^{2} + 2 (y - 1)^{2})

x^{2} y^{^{'}} - 3 x y = 4 x^{6}

What is the derivative of (x^2+3x^2) ?
The derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)
What is the first derivative of (x^2+3x^2) ?
The first derivative of (x^2+3x^2) is 2(x^2+3x)(2x+3)