What is the solution for (dy)/(dx)=((x+3y))/(y-3x) ?

The solution for (dy)/(dx)=((x+3y))/(y-3x) is y=(6x+sqrt(40x^2+c_{1)})/2 ,y=(6x-sqrt(40x^2+c_{1)})/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=((x+3y))/(y-3x)

\frac{d y}{d x} = \frac{( x + 3 y )}{y - 3 x}

y = \frac{6 x + 40 x ^{2} + c _{1}}{2}, y = \frac{6 x - 40 x ^{2} + c _{1}}{2}

Solution steps

\frac{d y}{d x} = \frac{( x + 3 y )}{y - 3 x}

Solve exact ODE:

y = \frac{6 x + 40 x ^{2} + c _{1}}{2}, y = \frac{6 x - 40 x ^{2} + c _{1}}{2}

y = \frac{6 x + 40 x ^{2} + c _{1}}{2}, y = \frac{6 x - 40 x ^{2} + c _{1}}{2}

x \to 3 lim (\frac{x ^{3} - 6 x ^{2} + 9}{x ^{2} - 9})

y = 7 x - 4 x^{2}, (- 3, - 57)

x \to 999 lim (x^{2} - 1)

\int \frac{4 x}{1 - 2 x} d x

\frac{s + 4}{s ^{2} + 4 s + 8}

What is the solution for (dy)/(dx)=((x+3y))/(y-3x) ?
The solution for (dy)/(dx)=((x+3y))/(y-3x) is y=(6x+sqrt(40x^2+c_{1)})/2 ,y=(6x-sqrt(40x^2+c_{1)})/2