What is the integral from-infinity to 0 of 1/(5-9x) ?

The integral from-infinity to 0 of 1/(5-9x) is diverges

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integral from-infinity to 0 of 1/(5-9x)

\int_{- \infty}^{0} \frac{1}{5 - 9 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{5 - 9 x} d x

Compute the indefinite integral:

\int \frac{1}{5 - 9 x} d x = - \frac{1}{9} ln ∣ 5 - 9 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{5 - 9 x} d x =

diverges

= diverges

3 e^{4 t}

4 y^{^{''}} - 4 y^{^{'}} - 3 y = cos (2 x)

\frac{d}{d a} (tan (a) + cot (a))

8 y^{^{''}} + 31 y = 0

\frac{d y}{d x} = \frac{( 2 x + x y ^{2} )}{4 y + y x ^{2}}

What is the integral from-infinity to 0 of 1/(5-9x) ?
The integral from-infinity to 0 of 1/(5-9x) is diverges