What is (\partial)/(\partial y)(3x^2-3y) ?

The answer to (\partial)/(\partial y)(3x^2-3y) is -3

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(\partial)/(\partial y)(3x^2-3y)

\frac{\partial}{\partial y} (3 x^{2} - 3 y)

- 3

Solution steps

\frac{\partial}{\partial y} (3 x^{2} - 3 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) - \frac{\partial}{\partial y} (3 y)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (3 y) = 3

= 0 - 3

Simplify

= - 3

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\int - \frac{e ^{2 t}}{2} d t

What is (\partial)/(\partial y)(3x^2-3y) ?
The answer to (\partial)/(\partial y)(3x^2-3y) is -3