What is (\partial)/(\partial x)(2x^4y-2) ?

The answer to (\partial)/(\partial x)(2x^4y-2) is 8x^3y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x^4y-2)

\frac{\partial}{\partial x} (2 x^{4} y - 2)

8 x^{3} y

Solution steps

\frac{\partial}{\partial x} (2 x^{4} y - 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{4} y) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (2 x^{4} y) = 8 y x^{3}

\frac{\partial}{\partial x} (2) = 0

= 8 y x^{3} - 0

Simplify

= 8 x^{3} y

\int \frac{1}{1 + e ^{6 x}} d x

n = 1 \sum \infty \frac{5}{n + 2}

\int (x^{3} + 3) d x

e^{x} \frac{d y}{d x} = e^{- y} + e^{2 x - y}

cos (x), sin (x)

What is (\partial)/(\partial x)(2x^4y-2) ?
The answer to (\partial)/(\partial x)(2x^4y-2) is 8x^3y