What is area 2cos(7x),2-2cos(7x),0<= x<= pi/7 ?

The answer to area 2cos(7x),2-2cos(7x),0<= x<= pi/7 is (4sqrt(3))/7+(2pi)/(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 2cos(7x),2-2cos(7x),0<= x<= pi/7

area

2 cos (7 x), 2 - 2 cos (7 x), 0 \leq x \leq \frac{π}{7}

\frac{4 3}{7} + \frac{2 π}{21}

Decimal Notation

1.28894 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{7}} ∣ 2 cos (7 x) - (2 - 2 cos (7 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{7}} ∣ 2 cos (7 x) - (2 - 2 cos (7 x)) ∣ d x : \frac{4 3}{7} + \frac{2 π}{21}

The area is:

= \frac{4 3}{7} + \frac{2 π}{21}

\int_{0}^{1} e^{- s t} \cdot t d t

\int e^{- 4 t} d t

\frac{d y}{d t} = 6 y + cos (3 t)

\int (\frac{t ^{2} + t + 1}{( t + 3 ) ^{3}}) d t

- y + 10 e^{- t} = y^{^{'}}

What is area 2cos(7x),2-2cos(7x),0<= x<= pi/7 ?
The answer to area 2cos(7x),2-2cos(7x),0<= x<= pi/7 is (4sqrt(3))/7+(2pi)/(21)