What is the sum from n=1 to infinity of 15(1/100)^n ?

The sum from n=1 to infinity of 15(1/100)^n is 5/33

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sum from n=1 to infinity of 15(1/100)^n

n = 1 \sum \infty 15 (\frac{1}{100})^{n}

\frac{5}{33}

Solution steps

n = 1 \sum \infty 15 (\frac{1}{100})^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 15 \cdot n = 1 \sum \infty (\frac{1}{100})^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= 15 (n = 0 \sum \infty (\frac{1}{100})^{n} - (\frac{1}{100})^{0})

n = 0 \sum \infty (\frac{1}{100})^{n} = \frac{100}{99}

= 15 (\frac{100}{99} - (\frac{1}{100})^{0})

Simplify

15 (\frac{100}{99} - (\frac{1}{100})^{0}) : \frac{5}{33}

= \frac{5}{33}

\frac{d}{d x} (\frac{x ^{2}}{2} + \frac{1}{x})

x (x^{5} + 2)

x \to 0 lim ((2 x^{2} + x)^{x})

y^{^{''}} + y = \frac{1}{( cos ( 2 x ) ) ^{\frac{3}{2}}}

x \to 2 + lim (\frac{8 + x}{2 - x})

What is the sum from n=1 to infinity of 15(1/100)^n ?
The sum from n=1 to infinity of 15(1/100)^n is 5/33