What is area y=sin^2(x),y=sin^3(x),x=0,x=pi ?

The answer to area y=sin^2(x),y=sin^3(x),x=0,x=pi is pi/2-4/3

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area y=sin^2(x),y=sin^3(x),x=0,x=pi

area

y = sin^{2} (x), y = sin^{3} (x), x = 0, x = π

\frac{π}{2} - \frac{4}{3}

Decimal Notation

0.23746 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x

Solve

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x : \frac{π}{2} - \frac{4}{3}

The area is:

= \frac{π}{2} - \frac{4}{3}

\int_{0}^{1} (2 x - 1)^{2} d x

y^{^{''}} + 400 y = sec (20 x)

x \to - 3 + lim (4 x^{2} - 7)

\int e^{2 x} (x^{2} + 2 x) d x

(t + 4)^{(\frac{2}{3})} (2 t^{2} - 4)^{3}

What is area y=sin^2(x),y=sin^3(x),x=0,x=pi ?
The answer to area y=sin^2(x),y=sin^3(x),x=0,x=pi is pi/2-4/3