What is the limit as x approaches 2 of sqrt(x^2+12) ?

The limit as x approaches 2 of sqrt(x^2+12) is 4

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limit as x approaches 2 of sqrt(x^2+12)

x \to 2 lim (x^{2} + 12)

4

Solution steps

x \to 2 lim (x^{2} + 12)

Plug in the value

x = 2

= 2^{2} + 12

Simplify

2^{2} + 12 : 4

= 4

\frac{d ^{2}}{d x ^{2}} (\frac{7}{8 x ^{6}})

f (x) = 6 x - 32 x, at x = 4

f (x) = \frac{x ^{2} + sec ( x )}{x - 2 e ^{x}}

f (x) = \frac{x ^{2} + 3}{x}

\frac{d y}{d x} (2 y) + \frac{( 1 + y ^{2} )}{x} = 1

What is the limit as x approaches 2 of sqrt(x^2+12) ?
The limit as x approaches 2 of sqrt(x^2+12) is 4