What is the derivative of-2sin(x+2sin(2x)) ?

The derivative of-2sin(x+2sin(2x)) is -2cos(x)+4cos(2x)

What is the first derivative of-2sin(x+2sin(2x)) ?

The first derivative of-2sin(x+2sin(2x)) is -2cos(x)+4cos(2x)

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\frac{d}{d x} (- 2 sin (x) + 2 sin (2 x))

- 2 cos (x) + 4 cos (2 x)

Solution steps

\frac{d}{d x} (- 2 sin (x) + 2 sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (2 sin (2 x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

= - 2 cos (x) + 4 cos (2 x)

\int (cos (x) - sec (x)) d x

(t + 5)^{\frac{2}{3}} (3 t^{2} - 2)^{3}

\frac{d y}{d x} + 5 y = 70, y (1) = 110

x \to 10 lim (\frac{7 x ^{2} - 70 x}{x ^{2} - 100})

\int cos (0.5 x) d x

What is the derivative of-2sin(x+2sin(2x)) ?
The derivative of-2sin(x+2sin(2x)) is -2cos(x)+4cos(2x)
What is the first derivative of-2sin(x+2sin(2x)) ?
The first derivative of-2sin(x+2sin(2x)) is -2cos(x)+4cos(2x)