What is the derivative of te^t ?

The derivative of te^t is e^t+e^tt

What is the first derivative of te^t ?

The first derivative of te^t is e^t+e^tt

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

t e^{t}

e^{t} + e^{t} t

Solution steps

\frac{d}{d t} (t e^{t})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = e^{t}

= \frac{d t}{d t} e^{t} + \frac{d}{d t} (e^{t}) t

\frac{d t}{d t} = 1

\frac{d}{d t} (e^{t}) = e^{t}

= 1 \cdot e^{t} + e^{t} t

Simplify

= e^{t} + e^{t} t

y^{^{'}} - 2 y = x^{2} e^{2 x}

\frac{d}{d x} (e^{5 x - 3})

\int (1 + x^{2})^{\frac{1}{2}} d x

\int 2 (sin (2 x))^{2} d x

\frac{\partial}{\partial x} (x y \cdot e^{x y})