What is the solution for (x^2+2y^2)dx=xydy ?

The solution for (x^2+2y^2)dx=xydy is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}

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(x^2+2y^2)dx=xydy

(x^{2} + 2 y^{2}) d x = x y d y

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

Solution steps

(x^{2} + 2 y^{2}) d x = x y d y

Solve Bernoulli ODE:

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

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What is the solution for (x^2+2y^2)dx=xydy ?
The solution for (x^2+2y^2)dx=xydy is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}