What is (\partial)/(\partial x)(2y-sin(x)) ?

The answer to (\partial)/(\partial x)(2y-sin(x)) is -cos(x)

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(\partial)/(\partial x)(2y-sin(x))

\frac{\partial}{\partial x} (2 y - sin (x))

- cos (x)

Solution steps

\frac{\partial}{\partial x} (2 y - sin (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (sin (x))

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= 0 - cos (x)

Simplify

= - cos (x)

\frac{d}{d x} (x^{3} e^{4 x})

t^{2} y^{^{''}} + 7 t y^{^{'}} + 5 y = t

\frac{d}{d x} (\frac{2}{5} x^{15})

t^{2} cos (2 t + 3 0^{\circ})

f (x) = 5 x sin (π x)

What is (\partial)/(\partial x)(2y-sin(x)) ?
The answer to (\partial)/(\partial x)(2y-sin(x)) is -cos(x)