What is the slope of (x^2+y^2)^2=4x^2y,(-1,1) ?

The slope of (x^2+y^2)^2=4x^2y,(-1,1) is 0

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slope of (x^2+y^2)^2=4x^2y,(-1,1)

slope

(x^{2} + y^{2})^{2} = 4 x^{2} y, (- 1, 1)

0

Solution steps

(x^{2} + y^{2})^{2} = 4 x^{2} y

Use implicit differentiation to find the slope of

(x^{2} + y^{2})^{2} = 4 x^{2} y

Implicit Derivative

\frac{d y}{d x}

(x^{2} + y^{2})^{2} = 4 x^{2} y : \frac{x ( - y ^{2} + 2 y - x ^{2} )}{- x ^{2} + y ^{3} + x ^{2} y}

\frac{x ( - y ^{2} + 2 y - x ^{2} )}{- x ^{2} + y ^{3} + x ^{2} y}

Find the slope at

(- 1, 1) : 0

0

x \to 0 lim (\frac{x + 2}{x})

\int e^{x} (2 x - 2) d x

\frac{d}{d x} (\frac{5}{x + 10})

f (x) = e^{9 x}

\frac{d}{d x} (e^{- x} \cdot cos (x))

What is the slope of (x^2+y^2)^2=4x^2y,(-1,1) ?
The slope of (x^2+y^2)^2=4x^2y,(-1,1) is 0