What is the sum from n=0 to infinity of ((7-8n))/(4+3n) ?

The sum from n=0 to infinity of ((7-8n))/(4+3n) is diverges

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sum from n=0 to infinity of ((7-8n))/(4+3n)

n = 0 \sum \infty \frac{( 7 - 8 n )}{4 + 3 n}

diverges

Solution steps

n = 0 \sum \infty \frac{7 - 8 n}{4 + 3 n}

Apply Series Divergence Test:

diverges

= diverges

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\int \frac{1}{8 - 4 x - 4 x ^{2}} d x

What is the sum from n=0 to infinity of ((7-8n))/(4+3n) ?
The sum from n=0 to infinity of ((7-8n))/(4+3n) is diverges