What is the integral of sec^5(x)tan(x) ?

The integral of sec^5(x)tan(x) is (sec^5(x))/5+C

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integral of sec^5(x)tan(x)

\int sec^{5} (x) tan (x) d x

\frac{sec ^{5} ( x )}{5} + C

Solution steps

\int sec^{5} (x) tan (x) d x

Apply u-substitution

: \int u^{4} d u

= \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{u ^{5}}{5}

Substitute back

u = sec (x)

= \frac{sec ^{5} ( x )}{5}

Add a constant to the solution

= \frac{sec ^{5} ( x )}{5} + C

f (x) = - \frac{13}{x ^{6}}

\int \frac{3}{t t ^{2} - 1} d t

e^{- x^{2}}

x \to + 0 lim (\frac{x}{x - 1})

\int_{2}^{4} \frac{x ( 2 x - 3 )}{6} d x

What is the integral of sec^5(x)tan(x) ?
The integral of sec^5(x)tan(x) is (sec^5(x))/5+C