What is the integral of (6x^6+3x^5+5x-4) ?

The integral of (6x^6+3x^5+5x-4) is (6x^7)/7+(x^6)/2+(5x^2)/2-4x+C

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integral of (6x^6+3x^5+5x-4)

\int (6 x^{6} + 3 x^{5} + 5 x - 4) d x

\frac{6 x ^{7}}{7} + \frac{x ^{6}}{2} + \frac{5 x ^{2}}{2} - 4 x + C

Solution steps

\int 6 x^{6} + 3 x^{5} + 5 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 x^{6} d x + \int 3 x^{5} d x + \int 5 x d x - \int 4 d x

\int 6 x^{6} d x = \frac{6 x ^{7}}{7}

\int 3 x^{5} d x = \frac{x ^{6}}{2}

\int 5 x d x = \frac{5 x ^{2}}{2}

\int 4 d x = 4 x

= \frac{6 x ^{7}}{7} + \frac{x ^{6}}{2} + \frac{5 x ^{2}}{2} - 4 x

Add a constant to the solution

= \frac{6 x ^{7}}{7} + \frac{x ^{6}}{2} + \frac{5 x ^{2}}{2} - 4 x + C

\frac{\partial}{\partial x} (e^{i x} cos (i y))

\int ln (x) \cdot \frac{1}{x} d x

\int (1 - x^{2} - x) x d x

\int \frac{x ^{4} + x - 16}{x ^{2} + 4} d x

ln (\frac{a ^{2} - z ^{2}}{a ^{2} + z ^{2}})

What is the integral of (6x^6+3x^5+5x-4) ?
The integral of (6x^6+3x^5+5x-4) is (6x^7)/7+(x^6)/2+(5x^2)/2-4x+C