What is the derivative of y=3(4x^2+4) ?

The derivative of y=3(4x^2+4) is 24x

What is the first derivative of y=3(4x^2+4) ?

The first derivative of y=3(4x^2+4) is 24x

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derivative of

y = 3 (4 x^{2} + 4)

24 x

Solution steps

\frac{d}{d x} (3 (4 x^{2} + 4))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (4 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 3 (\frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (4))

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (4) = 0

= 3 (8 x + 0)

Simplify

= 24 x

\frac{\partial}{\partial x} (z x + y)

\frac{\partial}{\partial x} ((x^{2} + y^{2}))

\frac{d}{d x} (\frac{x ^{2} - 7 x + 13}{x - 3})

y^{^{''}} - 2 y^{^{'}} = 4 t

\frac{d}{d x} (\frac{x}{10})

What is the derivative of y=3(4x^2+4) ?
The derivative of y=3(4x^2+4) is 24x
What is the first derivative of y=3(4x^2+4) ?
The first derivative of y=3(4x^2+4) is 24x