What is the limit as x approaches 2 of (\sqrt[3]{x}-2)/(x-8) ?

The limit as x approaches 2 of (\sqrt[3]{x}-2)/(x-8) is (2-\sqrt[3]{2})/6

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limit as x approaches 2 of (\sqrt[3]{x}-2)/(x-8)

x \to 2 lim (\frac{3 x - 2}{x - 8})

\frac{2 - 3 2}{6}

Decimal

0.12334 \dots

Solution steps

x \to 2 lim (\frac{3 x - 2}{x - 8})

Plug in the value

x = 2

= \frac{3 2 - 2}{2 - 8}

Simplify

\frac{3 2 - 2}{2 - 8} : \frac{2 - 3 2}{6}

= \frac{2 - 3 2}{6}

\int_{0}^{1} \frac{1}{x ^{\frac{19}{18}}} d x

\frac{d}{d x} (e^{x^{2}} + x^{2})

\int \frac{1}{- x ^{2} - 10 x} d x

y = ln (7 x^{2} + 9 y^{2})

\int ln (1 + 2 x) d x

What is the limit as x approaches 2 of (\sqrt[3]{x}-2)/(x-8) ?
The limit as x approaches 2 of (\sqrt[3]{x}-2)/(x-8) is (2-\sqrt[3]{2})/6