What is the integral of (2xy+x^2-1) ?

The integral of (2xy+x^2-1) is -y+x^2y+xy^2+C

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integral of (2xy+x^2-1)

\int (2 x y + x^{2} - 1) d y

- y + x^{2} y + x y^{2} + C

Solution steps

\int 2 x y + x^{2} - 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d y + \int x^{2} d y + \int 2 x y d y

\int 1 d y = y

\int x^{2} d y = x^{2} y

\int 2 x y d y = x y^{2}

= - y + x^{2} y + x y^{2}

Add a constant to the solution

= - y + x^{2} y + x y^{2} + C

9 sin (4 x)

w e^{w}

\frac{\partial}{\partial x} (\frac{x ^{\frac{5}{7}}}{e ^{x}})

x \to 0 lim (\frac{2}{x ^{2} + x} - \frac{2}{x})

\frac{3 t ^{2} + 4 t - 8}{t ^{\frac{3}{2}}}

What is the integral of (2xy+x^2-1) ?
The integral of (2xy+x^2-1) is -y+x^2y+xy^2+C